F(x)=x^2-5x+24

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Solution for F(x)=x^2-5x+24 equation: 



(F)=F^2-5F+24

We move all terms to the left:

(F)-(F^2-5F+24)=0

We get rid of parentheses

-F^2+F+5F-24=0

We add all the numbers together, and all the variables

-1F^2+6F-24=0

a = -1; b = 6; c = -24;
Δ = b2-4ac
Δ = 62-4·(-1)·(-24)
Δ = -60
Delta is less than zero, so there is no solution for the equation

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